双向链表节点的添加和删除(c#语言)
因为需求需要,所以直接写一个数据结构
直接上代码:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApplication2
{
class Program
{
static void Main(string[] args)
{
MyList<int> m = new MyList<int>();
m.add(1);
m.add(2);
m.add(3);
Console.WriteLine(m.getAndRemoveLast());
Console.WriteLine(m.getAndRemoveFirst());
Console.WriteLine(m.getAndRemoveLast());
Console.WriteLine(m.getAndRemoveLast());
Console.WriteLine(m.getAndRemoveLast());
m.add(3);
Console.WriteLine(m.getAndRemoveFirst());
m.add(4);
m.add(5);
m.add(6);
m.add(7);
m.add(8);
Console.WriteLine(m.getAndRemoveLast());
Console.WriteLine(m.getAndRemoveLast());
Console.WriteLine(m.getAndRemoveFirst());
Console.WriteLine(m.getAndRemoveFirst());
Console.Read();
}
}
//c#的集合太傻逼了,在此自制链表
class MyList<T>
{
public int count;//总数
public Node<T> first;//头节点
public Node<T> last;//尾节点
//添加函数
public void add(T t)
{
if (first == null)
{
first = new Node<T>(t);
last = first;
}
else
{
Node<T> node = new Node<T>(t);
node.next = first;
first.prev = node;
first = node;
}
count++;
}
/**
* 获取并删除最后一个元素
* **/
public T getAndRemoveLast()
{
Node<T> las = last;
if(last!=null)
{
count--;
if (first == last)
{
last = null;
first = last;
return las.t;
}
else
{
last = last.prev;
las.prev = null;
last.next = null;
return las.t;
}
}
else
{
return default(T);
}
}
/**
* 获取并删除第一个元素
* **/
public T getAndRemoveFirst()
{
Node<T> fir = first;
if (first != null)
{
count--;
if (first == last)
{
last = null;
first = last;
return fir.t;
}
else
{
first = first.next;
fir.next = null;
first.prev = null;
return fir.t;
}
}
else
{
return default(T);
}
}
}
//节点类
class Node<T>
{
public Node<T> next;
public Node<T> prev;
public T t;
public Node(T t)
{
this.t = t;
next = null;
prev = null;
}
}
}
fixed
没有一个冬天不可逾越,没有一个春天不会来临。最慢的步伐不是跬步,而是徘徊,最快的脚步不是冲刺,而是坚持。